Question 257201: sinA+sinB+sinC=3 find the value of cosA+cosB+cosC
Answer by jsmallt9(3758)   (Show Source):
You can put this solution on YOUR website! Since the maximum value for sin is 1 and since you have three sin's adding up to 3, each of the sin's must be 1! (If any of the sin's are not 1, then there is no way for the other two to make up the difference.) So A = B = C = 90 degrees or any angle coterminal with 90 degrees. And the cos of 90 degrees is zero. So cos(A)+cos(B)+cos(C) = 0+0+0 = 0.
|
|
|
