You can put this solution on YOUR website! Twice the sum of three consecutive multiples of 15 is 270. What are the three
multiples of 15?
Let m be the smallest multiple. Then
2*(m*15 + (m+1)*15 + (m+2)*15) = 270
15m + 15m + 15 + 15m + 30 = 135
Solve for m.