SOLUTION: (t+k)/2=(t^2-t-7)/(2+2t) solve for t.

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Question 257092: (t+k)/2=(t^2-t-7)/(2+2t)
solve for t.
Found 2 solutions by stanbon, drk:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
(t+k)/2=(t^2-t-7)/(2+2t)
solve for t.
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Multiply both sides by 2 to get:
(t+k) = (t^2-t-7)/(1+t)
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Multiply both sides by 1+t to get:
t + t^2 + k + kt = t^2-t-7
2t+kt = -(k+7)
t(2+k) = -(k+7)
t = -(k+7)/(k+2)
======================
Cheers,
Stan H.

Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
We have the following:
%28t%2Bk%29%2F2 =%28t%5E2-t-7%29%2F%282%2B2t%29+
step 1 - cross multiply to get
%28t%2Bk%29%282%2B2t%29+=+%28t%5E2-t-7%29%2A%282%29
step 2 - distribute to get
2t%5E2+%2B+2t+%2B+2k+%2B+2kt+=+2t%5E2+-+2t+-+14
simplify and get
4t+%2B+2k+%2B+2kt+%2B+14+=+0
pulling out the GCF of t, we get
t%284%2B2k%29+=+-2k+-+14
dividing, we get
t+=+%28-2k-14%29%2F%284%2B2k%29
simplifying, we get
t+=+%28-k-7%29%2F%282%2Bk%29