SOLUTION: A rectangle is 4 meters longer than it's wide. If the length is increased by 2 meters and the width is increased by 1 meter, the area is increased by 36 meters squared. Find the wi
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Question 257055: A rectangle is 4 meters longer than it's wide. If the length is increased by 2 meters and the width is increased by 1 meter, the area is increased by 36 meters squared. Find the width of the original rectangle. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! rectangle is 4 meters longer than it's wide. If the length is increased by 2 meters and the width is increased by 1 meter, the area is increased by 36 meters squared. Find the width of the original rectangle.
:
Let x = the width of the original rectangle
It says "is 4 meters longer than it's wide", therefore:
L = (x+4)
:
"If the length is increased by 2 meters and the width is increased by 1 meter,"
New length = L+2
Replace L with (x+4)
x+4 + 2 = (x+6) is the new length
and
New width = x+1
:
New area - old area = 36 sq/m
(x+6)(x+1) - x(x+4) = 36
FOIL
x^2 + x + 6x +6 - x^2 - 4x = 36
Combine like term
x^2 - x^2 + x + 6x - 4x = 36 - 6
3x = 30
x =
x = 10 m is original width
:
:
Check solution by finding the area of each
16 * 11 = 176
14 * 10 = 140
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difference 36
