SOLUTION: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $1
Question 25705: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have? Answer by Paul(988) (Show Source):
You can put this solution on YOUR website! Let the number of dimes be x
Let the number of nickels be y
Nickel value times 100 = 5
Dime value times 100 = 10
5.65 times 100 = 565
10.45 times 100 = 1045
5x+10y=565
5x=565-10y
x=113-2y (subsituition)
Dimes doubled = 2x
Nickles increased by 8 = y+8
10(2x)+5(y+8)=1045
20x+5y+40=1045
Subsitute for x
20(113-2y)+5y=1005
2260-40y+5y=1005
-35y=-1255
y=36 (rounded)
x=41
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