Question 256859: How do I use the points on the line an the slope of the line to find 3 additional point in which the line passes
Problem:
(0,-9) slope -2
Could someone please give me step by step instruction and show how this problem is solved
Thanks
Jen
Found 2 solutions by drk, ankor@dixie-net.com:
Answer by drk(1908)   (Show Source):
You can put this solution on YOUR website! WE have the slope intercept formula as
Using our given information, we get
Choose 3 values of x and then find 3 values of y to get your points (coordinates).
x: . . . . . (-1) . . . . . (0) . . . . . .(1)
Y: . . . . . .(-7) . . . . .(-9) . . . . (-11)
so your three coordinates are:
(-1,-7)
(0,-9)
(1,-11)
Answer by ankor@dixie-net.com(22740)  (Show Source):
You can put this solution on YOUR website! Problem:
(0,-9) slope -2
:
Use the point/slope equation; y - y1 = m(x - x1)
In this problem
x1 = 0
y1 = -9
m = -2
:
Substitute in the equation
y - (-9) = -2(x - 0)
y + 9 = -2x + 0
y = -2x - 9; this is the equation for the given pair and slope
:
3 additional points
for x=-2;
y = -2(-2) - 9
y = +4 - 9
y = -5
the ordered pair -2,-5
:
for x=-1;
y = -2(-1) - 9
y = 2 - 9
y = -7
the ordered pair -1,-7
:
for x=+2
y = -2(2) - 9
y = -4 - 9
y = -13
ordered pair 2,-13
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