SOLUTION: A jar contains 5 red marbles and 3 black marbles. 2 marbles are drawn with replacement. what is the probability that one is black and one is red?
the chances of getting a red is 5
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the chances of getting a red is 5
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Question 256850: A jar contains 5 red marbles and 3 black marbles. 2 marbles are drawn with replacement. what is the probability that one is black and one is red?
the chances of getting a red is 5/8 and the black is 3/8, this I get. and the chance of getting either one is 2/8 or 1/4.
So, here is how I approached it.....
5/8+3/8-2/8= 6/8
6/8 x 5/8=30/64 or 15/32
But I am not sure if this is correct procedure. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A jar contains 5 red marbles and 3 black marbles. 2 marbles are drawn with replacement. what is the probability that one is black and one is red?
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P(2 black) = 3C2/8C2 = 3/28
P(2 red) = 5C2/8C2 = 10/28
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P(one black and one red) = 1-[3/28+10/28) = 15/28
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Cheers,
Stan H.
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