SOLUTION: For which value is f (x) undefined: f(x)= cosx/1-cos2x

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Question 256805: For which value is f (x) undefined: f(x)= cosx/1-cos2x
Found 3 solutions by Fombitz, stanbon, jsmallt9:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
f(x) is undefined when the denominator equals zero.
1-cos%282x%29=0
cos%282x%29=1
2x=pi%2F2 or 2x=%283%2F2%29pi
x=pi%2F4 or x=%283%2F4%29pi

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
For which value is f (x) undefined: f(x)= cosx/1-cos2x
----
Undefined when the denominator is zero.
Solve 1-cos(2x) = 0
cos(2x) = 1
2x = 0 or pi
x = 0 or pi/2
===================
Cheers,
Stan H.

Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
(NOTE: A different solution from another tutor starts off correctly but it has an error.)

As stated in the other solution, we do want to find where
1 - cos(2x) = 0
or
1 = cos(2x)

The error comes next. The cos function is 1 for 0 radians, not pi%2F2. So:
2x+=+0+%2B+2pi%2An where n is any integer.
For x, we divide both sides by 2:
x+=+0%2F2+%2B+2pi%2An%2F2 where n is any integer.
which simplifies to:
x+=+0+%2B+pi%2An where n is any integer.