Question 25678: A Freight train is traveling 30milesper hour. An automobile starts out from the same place 1 hour later and overtakes the traimnin 3 hours. What was the rate of the automobile. could you work this one out step by step. i would appreciate it so so so so much. thank you.
Answer by venugopalramana(3286)   (Show Source):
You can put this solution on YOUR website! SEE FOLLOWING EXAMPLES WHICH ARE SIMILAR AND TRY. IF YOU STILL HAVE PROBLEM COME BACK
----------------------------------------------------------------
A motorboat starts out and travels 9 miles an hour. In 3 hours another motorboat rraveling 18 miles an hour starts out to overtake the first one. In how many hours will thei sceond boat overtake the first.
1 solutions
Answer 13785 by venugopalramana(735) About Me on 2006-01-27 00:19:56 (Show Source):
A motorboat starts out and travels 9 miles an hour. In 3 hours another motorboat rraveling 18 miles an hour starts out to overtake the first one. In how many hours will thei sceond boat overtake the first.
RELATIVE SPEED WHILE TRAVELLING IN SAME DIRECTIONS = S2-S1=18-9=9 MPH.
INITIAL DISTANCE OF SEPERATION = DISTANCE TRAVELLED BY FIRST BOAT IN 3 HOURS
= 3*9=27 MILES.
FINAL DISTANCE OF SEPERATION=0
HENCE DISTANCE TO BE COVERED WHEN BOTH BOATS ARE TRAVELLING IN SAME DIRECTION =27-0=27
TIME TAKEN =DISTANCE / RELATIVE SPEED = 27 / 9 = 3 HRS.
Travel_Word_Problems/25659: C and D start from two points 480 miles apart and travel toward eash other. They meet in 8 hours. If C travels 6 miles per hour faster than D, find their rates.
1 solutions
Answer 13784 by venugopalramana(735) About Me on 2006-01-27 00:06:59 (Show Source):
SEE THE FOLLOWING PROBLEM WHICH IS SIMILAR
--------------------------------------------------------------------------
Two men, A and B, start toward each other at the same time from points 510 miles apart. If they travel 40 and 4 milea an hour respectively, in how many hours will they meet.
RELATIVE SPEED WHILE TRAVELLING IN OPPOSITE DIRECTION TO EACH OTHER = S1+S2=40+4=44 MPH.
INTIAL DISTANCE OF SEPERATION =510 MILES.
FINAL DISTANCE OF SEPERATION =0
HENCE DISTANCE TO BE COVERED TOGETHER = 510 -0 =510 MILES
TIME NEEDED =DISTANCE / RELATIVE SPEED = 510/44 HRS
----------------------------------------------------------------------------------
IN YOU CASE ,WE GET..WITH X AND X+6 SPEEDS AS GIVEN,
8= 480/(X+X+6)
8(2X+6)=480
2X+6=480/8=60
2X=60-6=54
54/2=27.
HENCE THEIR SPEEDS ARE 27 AND 33 MPH.
Travel_Word_Problems/25660: Two men, A and B, start toward each other at t
|
|
|
