SOLUTION: -(7a^2b^3) (-14ab^-3)
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Question 256447
:
-(7a^2b^3) (-14ab^-3)
Answer by
drk(1908)
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We are given:
(i)
First, multiply -7 and -14 to get
(ii) {{(98a^2b^3) (ab^-3)}}}
Second, multiply the a's to get
(iii) {{(98a^3b^3) (b^-3)}}}
Third, multiply the b's to get
(iv)
However, b^0 = 1, so we get