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Question 256411: find the graph of the parabola y2(squared)+6y+8x+25=0
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! find the graph of the parabola y^2+6y+8x+25=0
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Complete the square on the y-terms:
y^2+6y+9 = -8x-25+9
(y+3)^2 = -8x-16
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solve for "x":
8x = -(y+3)^2 - 16
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x = (-1/8)(y+3)^2 - 2
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Graph the parabola:
Vertex at (-2,-3)
Opens to the left.
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If y = -3, x = -2
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That is enough information to sketch the graph.
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Cheers,
Stan H.
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