SOLUTION: Use substitution to solve 4t^1/3 - 5t^1/6 + 1 = 0. I first tried multiplying the exponent of 4t^1/3 by 3 to get 4t^3 and was wondering if that was correct, if not what is? If it

Algebra ->  Expressions-with-variables -> SOLUTION: Use substitution to solve 4t^1/3 - 5t^1/6 + 1 = 0. I first tried multiplying the exponent of 4t^1/3 by 3 to get 4t^3 and was wondering if that was correct, if not what is? If it      Log On


   

Question 256341: Use substitution to solve 4t^1/3 - 5t^1/6 + 1 = 0.
I first tried multiplying the exponent of 4t^1/3 by 3 to get 4t^3 and was wondering if that was correct, if not what is? If it is, where do I go from there, do I just repeat it by multiplying 6 to the other side and setting it all equal to -1?
Thanks.
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
substituting x for t^(1/6)

4x^2 - 5x + 1 = 0

factoring ___ (4x - 1) (x - 1) = 0

4x - 1 = 0 ___ x = 1/4 ___ substituting ___ t^(1/6) = 1/4 ___ t = 4^(-6)

x - 1 = 0 ___ x = 1 ___ substituting ___ t^(1/6) = 1 ___ t = 1