SOLUTION: seven times the larger of two consecutive integers is forty three less than eight times the smaller. what are the integers?

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Question 256267: seven times the larger of two consecutive integers is forty three less than eight times the smaller. what are the integers?
Answer by College Student(505) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = integer
Let x+1 = the consecutive integer

If seven times the larger of two consecutive integers is forty three less than eight times the smaller, the equation becomes: 7%28x%2B1%29=8x-43

Now solve for x, then check your answer.
7%28x%2B1%29=8x-43
7x%2B7=8x-43
7%2B43=8x-7x
50=x

Check:
7%28x%2B1%29=8x-43
7%2850%2B1%29=%288%2A50%29-43
7%2A51=400-43
357=357 The answer checks!

Your integers are: 50 and 51