SOLUTION: two buses that are 90 mi apart travel toward each other on an interstate highway. the slower bus which departs at 9:30 AM travels 5mi/h slower than the buse that departs at 9:45 AM

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Question 256164: two buses that are 90 mi apart travel toward each other on an interstate highway. the slower bus which departs at 9:30 AM travels 5mi/h slower than the buse that departs at 9:45 AM. At 10:30 AM the buses pass each other. Determine the rate of each bus.
Must use two variables.
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
"the slower bus which departs at 9:30 AM travels 5mi/h slower" ___ S + 5 = F

r * t = d

(S * 1) + (F * 3/4) = 90 ___ 4S + 3F = 360

substituting ___ 4S + 3S + 15 = 360 ___ 7S = 345 ___ S = 345/7

substituting ___ 345/7 + 35/7 = F ___ 380/7 = F