SOLUTION: what is g-f(x) where f(x) is x+1 and g(x) is x^2-1
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Question 256149
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what is g-f(x) where f(x) is x+1 and g(x) is x^2-1
Answer by
drk(1908)
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g(x) - f(x) = x^2-1 -(x+1)
g(x) - f(x) = (x+1)(x-1) - (x+1)
g(x) - f(x) = (x+1)[x-1-1]
g(x) - f(x) = (x+1)[x-2]