SOLUTION: I have three different sets of balls marked 0-9, what are the odds of getting any given set of 3 numbers? EX: 123 or 578
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Question 256132: I have three different sets of balls marked 0-9, what are the odds of getting any given set of 3 numbers? EX: 123 or 578 Found 2 solutions by drk, edjones:Answer by drk(1908) (Show Source):
You can put this solution on YOUR website! Odds are failure over success.
We ned probability.
p(3 numbers) = 10C3/(10*9*8) = 1/6
success = 1
fail = 5
total = 6
So, I would say,
5:1
You can put this solution on YOUR website! 3 odd, 0 even=odd
2odd, 1 even=even
1odd, 2 even=odd
0 odd, 3 even=even
.
Since 1/2 the balls are even and 1/2 odd, (zero is even) then the probability is 1/2 and the odds are even or 1 to 1.
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