Question 256117: I do not have a stat calculator and do not know where to even begin.
Daily output of Marathon’s Garyville, Lousiana, refinery is normally distributed with a mean of 232,000 barrels of crude oil per day with a standard deviation of 7,000 barrels. (a) What is the probability of producing at least 232,000 barrels? (b) Between 232,000 and 239,000 barrels? (c) Less than 239,000 barrels? (d) Less than 245,000 barrels? (e) More than 225,000 barrels?
Answer by drk(1908)   (Show Source):
You can put this solution on YOUR website! (a) What is the probability of producing at least 232,000 barrels?
50% of them are at least 232,000, so prob = 1/2
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(b) Between 232,000 and 239,000 barrels?
This is from sigma = 0 to sigma = 1, so we have 34%
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(c) Less than 239,000 barrels?
this is 50% + 34% = 84% ~ .84
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(d) Less than 245,000 barrels? (e) More than 225,000 barrels?
We need to fin a z-score: (245000-232000)/7000 = 13000/7000 = 1.85.
.4678 + .5 = .9678
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