|
Question 256075: Please help me with this
Point A (-4,1) is in the standard (x,y) coordinate plane. What must be the coordinates of point B so that the line x=2 is the perpendicular bisector of AB?
Found 3 solutions by richwmiller, solver91311, stanbon: Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! x=2 is a vertical line going through (2,y)
A perpendicular line would be horizontal going through (2,y) and from the point (-4,1) we know the y value is 1 so the point C intersection of the lines is (2,1)
An equation for that line could be y=1 (There are an infinite number of such lines)
2-(-4)=6
2+6=8
since x=2 bisects the line AB
point B should be (8,1)
Answer by solver91311(24713) (Show Source): Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Point A (-4,1) is in the standard (x,y) coordinate plane. What must be the coordinates of point B so that the line x=2 is the perpendicular bisector of AB?
-------------------
Draw the picture so you can see what you are doing.
Plot the point: (-4,1)
Draw the line x=2; it will pass thru (2,1) and (2,1) will be the mid-point
of AB.
----
Let the coordinates of B be (x,y):
(-4+x)/2 = 2
-4+x = 4
x = 8
--------
(1+y)/2 = 1
1+y = 2
y = 1
-------
The coordinate of B are (8,1)
===================================
Cheers,
Stan H.
|
|
|
| |