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| Question 256075:  Please help me with this
 Point A (-4,1) is in the standard (x,y) coordinate plane. What must be the coordinates of point B so that the line x=2 is the perpendicular bisector of AB?
 Found 3 solutions by  richwmiller, solver91311, stanbon:
 Answer by richwmiller(17219)
      (Show Source): 
You can put this solution on YOUR website! x=2 is a vertical line going through (2,y) A perpendicular line would be horizontal going through (2,y) and from the point (-4,1) we know the y value is 1 so the point C intersection of the lines is (2,1)
 An equation for that line could  be y=1 (There are an infinite number of such lines)
 2-(-4)=6
 2+6=8
 since x=2 bisects the line AB
 point B should be (8,1)
Answer by solver91311(24713)
      (Show Source): Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! Point A (-4,1) is in the standard (x,y) coordinate plane. What must be the coordinates of point B so that the line x=2 is the perpendicular bisector of AB? -------------------
 Draw the picture so you can see what you are doing.
 Plot the point: (-4,1)
 Draw the line x=2; it will pass thru (2,1) and (2,1) will be the mid-point
 of AB.
 ----
 Let the coordinates of B be (x,y):
 (-4+x)/2 = 2
 -4+x = 4
 x = 8
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 (1+y)/2 = 1
 1+y = 2
 y = 1
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 The coordinate of B are (8,1)
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 Cheers,
 Stan H.
 
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