Question 256057: i need help with this:
Find the common solution to the following pair of lines by graphing them on the same axes.
3x + 2y = 6
x - y = 2
The lines intersect at (?,? ).
the answer is (2,0). i was wondering how they got (2,0). I have graphed this every way i could think of and never got (2,0). here are the answers i got:
(-2,4), (-4,2), (2,4), (4,2), (4,-2), (2,-4), (-2,-4), (-4,-2).
did i do that right and there's a glitch? or did i do that wrong without realizing?
Found 2 solutions by solver91311, CharlesG2:
Answer by solver91311(24713)   (Show Source):
Answer by CharlesG2(834)  (Show Source):
You can put this solution on YOUR website! " i need help with this:
Find the common solution to the following pair of lines by graphing them on the same axes.
3x + 2y = 6
x - y = 2
The lines intersect at (?,? ).
the answer is (2,0). i was wondering how they got (2,0). I have graphed this every way i could think of and never got (2,0). here are the answers i got:
(-2,4), (-4,2), (2,4), (4,2), (4,-2), (2,-4), (-2,-4), (-4,-2).
did i do that right and there's a glitch? or did i do that wrong without realizing? "
3x+2y=6
2y=-3x+6
y=(-3/2)x+3
x-y=2
-y=-x+2
y=x-2
the graph does indeed cross at (2,0)
we could also set the equations equal to one another and solve for x
(-3/2)x+3=x-2
-3x+6=2x-4
-5x=-10
x=2
plug x=2 into each and solve for y
3x + 2y = 6
x - y = 2
3(2)+2y=6
6+2y=6
2y=0
y=0
(2)-y=2
-y=0
y=0
I hope all this helps
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