SOLUTION: A boy buys oranges at 3 for $1 and will sell them at 5 for $2. If he wishes to make a profit of $10, how many oranges must he sell?

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: A boy buys oranges at 3 for $1 and will sell them at 5 for $2. If he wishes to make a profit of $10, how many oranges must he sell?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 256010: A boy buys oranges at 3 for $1 and will sell them at 5 for $2. If he wishes to
make a profit of $10, how many oranges must he sell?
Found 2 solutions by josmiceli, nerdybill:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = number that he must sell
In words:
(cost/orange x oranges sold) - (cost/orange x oranges bought) = profit
%28200%2F5%29%2Ax+-+%28100%2F3%29%2Ax+=+1000
(in cents)
Multiply both sides by 15
600x+-+500x+=+15000
100x+=+15000
x+=+150
He must sell 150 oranges
check:
%28200%2F5%29%2Ax+-+%28100%2F3%29%2Ax+=+1000
%28200%2F5%29%2A150+-+%28100%2F3%29%2A150+=+1000
150%2A%28200%2F5+-+100%2F3%29+=+1000
200%2F5+-+100%2F3+=+20%2F3
Multiply both sides by 15
600+-+500+=+100
OK

Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
A boy buys oranges at 3 for $1 and will sell them at 5 for $2. If he wishes to
make a profit of $10, how many oranges must he sell?
.
Let x = number of oranges sold
then
"amount sold" - "cost" = "profit"
2(x/5) - 1(x/3) = 10
2(x/5) - (x/3) = 10
Multiplying both sides by 15:
6x - 5x = 150
x = 150