SOLUTION: Hello, I am having difficulty with this problem. I attempted to create a rectangle and solve it but my answer still turns out wrong, could you please help me. If the coordinates

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Question 255963: Hello, I am having difficulty with this problem. I attempted to create a rectangle and solve it but my answer still turns out wrong, could you please help me.
If the coordinates of a parallelogram are Q(3,-2),R(7,-2), S(9,3) T(5,3)then
what is the area of QRST?

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
Hello, I am having difficulty with this problem. I attempted to create a rectangle and solve it but my answer still turns out wrong, could you please help me.
If the coordinates of a parallelogram are Q(3,-2),R(7,-2), S(9,3) T(5,3)then
what is the area of QRST?



The area of a parallelogram is given by the
formula 

A=base%2Aheight

The base is QR which is 4 units (count the units using the
x-axis as a measuring stick).

Now we draw in the height.  I'll draw it in green 



The height is the green line segment which is 5 units long
(count the units using the y-axis as a measuring stick).

So  A=base%2Aheight
    A=4%2A5
    A=20 square units.

Edwin