SOLUTION: A parallelogram has sides of legnths of 3 and 5, and one angle is 50'. find the lengths of the diagonals.

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Question 255943: A parallelogram has sides of legnths of 3 and 5, and one angle is 50'. find the lengths of the diagonals.
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!



First we'll find this diagonal marked d.



Let's erase the upper half of the parallelogram:



Now we have SAS, so we use the law of cosines:

d%5E2=3%5E2%2B5%5E2-2%2A3%2A5%2Acos%28%2250%B0%22%29

d%5E2=9%2B25-30cos%28%2250%B0%22%29

d%5E2=34-30%28.6427876097%29

d%5E2=14.71637171

d=3.836192345

Now we go back to the original parallelogram.
Two adjacent angles of a parallelogram are
supplementary, so since 180° - 50° = 130°



Next we'll find this diagonal marked d'.



Let's erase the upper half of the parallelogram:



Again we have SAS, so we use the law of cosines again:

%22d%27%22%5E2=3%5E2%2B5%5E2-2%2A3%2A5%2Acos%28%22130%B0%22%29

%22d%27%22%5E2=9%2B25-30cos%28%22130%B0%22%29

%22d%27%22%5E2=34-30%28-.6427876097%29

%22d%27%22%5E2=53.28362829

%22d%27%22=7.299563569

Edwin