SOLUTION: 42. Find b^2 - 4ac and the number of real solutions to each equation.
14. Solve each equation by using the quadratic formula. -8q^2+2q+1=0
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-> SOLUTION: 42. Find b^2 - 4ac and the number of real solutions to each equation.
14. Solve each equation by using the quadratic formula. -8q^2+2q+1=0
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Question 255667: 42. Find b^2 - 4ac and the number of real solutions to each equation.
14. Solve each equation by using the quadratic formula. -8q^2+2q+1=0 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 42. Find b^2 - 4ac and the number of real solutions to each equation.
If you have a quadrate: y = ax^2 + bx + c
The roots are x = [-b +- sqrt(b^2-4ac)]/(2a)
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If b^2 - 4ac = 0 the two roots are both x = -b/2a
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If b^2 - 4ac > 0 you will have two Real Number solutions
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If b^2 -4ac < 0 you will get two Complex Number solutions
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14. Solve each equation by using the quadratic formula.
-8q^2+2q+1=0
x = [-2 +- sqrt(4 - 4*-8*1)]/(-16)
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x = [-2 +- sqrt(36)]/(-16)
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x = [-2 +- 6]/(-16)
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x = [-8/-16] or x = [4/-16]
x = 1/2 or x = -1/4
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Cheers,
Stan H.
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