SOLUTION: Identify the vertex and the y-intercept of the graph of the function y = -3(x + 2)^2 + 5

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Identify the vertex and the y-intercept of the graph of the function y = -3(x + 2)^2 + 5      Log On


   



Question 255522: Identify the vertex and the y-intercept of the graph of the function y = -3(x + 2)^2 + 5
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Identify the vertex and the y-intercept of the graph
of the function y = -3(x + 2)^2 + 5
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The function is in the vertex form y = a(x-h)^2+k
where the vertex is (h,k).
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Your problem: vertex is (-2,5)
When x = zero, y = -3*2*2+5 = -7
so the y-intercept is (0,-7.
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Since a = -3 is negative the parabola opens downward.
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graph%28400%2C300%2C-10%2C10%2C-20%2C10%2C-3x%5E2-12x-7%29
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Cheers,
stan H.