SOLUTION: v^9 over v^5

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Question 255500: v^9 over v^5
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
2^3=8
2^2=4
2^1=2
2^3/2^1=2^2
8/2=4
what did I do with the exponents I subtracted them
to divide two like terms to powers
subtract he powers
v^9/v^5=v^4