SOLUTION: a freight train leaves a station traveling 60 miles per hour. thirty minutes later a passenger train leaves the station in the same direction on a parallel track at a speed of 72 m

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Question 255405: a freight train leaves a station traveling 60 miles per hour. thirty minutes later a passenger train leaves the station in the same direction on a parallel track at a speed of 72 miles per hour. How long will it take the passenger train to catch the freight train?
Found 2 solutions by rfer, josmiceli:
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
first train is 30 miles ahead
overtake speed is 12 mph
30/12=2.5 hrs= 2 hrs 30 min

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Imagine you have a stopwatch and you start it when
the 2nd train leaves. You are all-knowing and powerful,
and can stop the stopwatch when the trains meet.
How far has the 1st train gone when you start the stopwatch?
d+=+r%2At
r+=+60 mi/hr
t+=+1%2F2 hr
d+=+60%2A%281%2F2%29
d+=+30 mi
Now the 2 train will travel different distances but for the same time
on the stopwatch (t%5B1%5D+=+t%5B2%5D)
For the 2nd train:
d%5B2%5D+=+r%5B2%5D%2At%5B2%5D
r%5B2%5D+=+72 mi/hr
d%5B2%5D+=+72%2At%5B2%5D
The 1st train has 30 mi less to travel
d%5B2%5D+-+30+=+60%2At%5B2%5D
d%5B2%5D+=+60%2At%5B2%5D+%2B+30
Use d%5B2%5D in the 1st equation for d%5B2%5D in the 2nd equation
72%2At%5B2%5D+=+60%2At%5B2%5D+%2B+30
12%2At%5B2%5D+=+30
t%5B2%5D+=+2.5 hrs
It will take the passenger train 2.5 hrs to catch the freight train
check:
The 1st train has traveled for 2.5+%2B+.5+=+3 hrs
d%5B1%5D+=+60%2A3 mi
d%5B1%5D+=+180 mi
And the 2nd train's distance is
d%5B2%5D+=+72%2A2.5
d%5B2%5D+=+180 mi
These are the TOTAL distances the trains must travel
and they are equal as they must be when they meet