SOLUTION: if k(x)={(2,3),(4,5),(3,-2),(1,-5), (0,-1)} find {{{ k^-1(x)}}} I'm supposed to be trying to solve for {{{ k^1(x) }}} Please help! :D It will be appreciated!

Algebra ->  Functions -> SOLUTION: if k(x)={(2,3),(4,5),(3,-2),(1,-5), (0,-1)} find {{{ k^-1(x)}}} I'm supposed to be trying to solve for {{{ k^1(x) }}} Please help! :D It will be appreciated!       Log On


   

Question 255384: if k(x)={(2,3),(4,5),(3,-2),(1,-5), (0,-1)} find +k%5E-1%28x%29
I'm supposed to be trying to solve for +k%5E1%28x%29+
Please help! :D It will be appreciated!
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
We have the following set
k(x)=((2,3),(4,5),(3,-2),(1,-5), (0,-1))
To find the inverse, k^(-1)(x) just reverse the x and y values to get
k^(-1)(x) = ((3,2),(5,4),(-2,3),(-5,1),(-1,0))