SOLUTION: how do i write an equation in slope-intercept form for the lone that is perpendicular to the given lone and passes through the given point y=-3x+4;(6,-2)

Algebra ->  Graphs -> SOLUTION: how do i write an equation in slope-intercept form for the lone that is perpendicular to the given lone and passes through the given point y=-3x+4;(6,-2)      Log On


   



Question 255361: how do i write an equation in slope-intercept form for the lone that is perpendicular to the given lone and passes through the given point
y=-3x+4;(6,-2)

Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
step 1 - solve the equation for y. That is already done and given as
(i) y+=+3x+%2B+4
step 2 - find the slope of (i) and we get m = 3.
step 3 find perpendicular slope. m = 3, so perpendicular means flip and change sign. Perp m = -1/3.
step 4 - using new slope and (6,-2) we put that information into
y=mx%2B+bto get
-2+=+%28-1%2F3%29%2A6+%2B+b
-2+=+-2+%2B+b
b+=+0
step 5 - write the answer as
y+=+%28-1%2F3%29x+%2B+0