Question 255262: Mark and Bob start at the same time to ride their bikes from Furman to Asheville, 60 miles away. Mark travels 4 miles an hour slower than Bob. Bob reaches Asheville and at once turns back, meeting Mark 12 miles from Asheville. What is
Mark’s rate, in miles per hour?
Answer by palanisamy(496)   (Show Source):
You can put this solution on YOUR website! Let the speed of Bob = x
Given, Mark travels 4 miles an hour slower than Bob
So the speed of Mark = x-4
Bob reaches Asheville which is 60 miles away and at once turns back, meeting Mark 12 miles from Asheville.
Therefore the time taken by Bob to travel 72 miles is equal to the time taken by Mark to travel 48 miles
72/x = 48/(x-4)
72(x-4) = 48x
Dividing by 24, we get
3(x-4) = 2x
3x-12 = 2x
3x-2x = 12
x = 12
Therefore,the speed of Bob = 12 miles/hr
the speed of Mark = 12-4 = 8 miles/hr
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