SOLUTION: Find the dimensions of a rectangle whose area is 180 square meters and whose perimeter is 54 meters.

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Question 255219: Find the dimensions of a rectangle whose area is 180 square meters and whose perimeter is 54 meters.
Answer by palanisamy(496) About Me  (Show Source):
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Let the length of the rectangle = x
and the width of the rectangle = y
Given, perimeter 2(x+y) = 54 mts
x+y = 54/2
x+y = 27
y = 27-x ...(1)
Also, area xy = 180
x(27-x) = 180
27x-x^2 = 180
-x^2+27x-180 = 0
x^2-27x+180 = 0
(x-15)(x-12)= 0
x = 15 and x = 12
Therefore, the length of the rectangle = 15 mts
and the width of the rectangle is y = 27-15 = 12 mts