SOLUTION: what is the solution set of (6x+4)squared=77

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Question 255207: what is the solution set of (6x+4)squared=77
Answer by checkley77(12844) About Me  (Show Source):
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(6x+4)squared=77
36x^2+48x+16-77=0
36x^2+48x-61=0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x=(-48+-sqrt[48^2-4*36*-61])/2*36
x=(-48+-sqrt[2,304+8,784])/72
x=(-48+-sqrt11,088)/72
x=(-48+-105.2996)/72
x=(-48+105.2996)/72
x=57.2996/72
x=.796 ans.
x=(-48-105.2996)/72
x=-153.2996/72
x=-2.129 ans.