SOLUTION: A freight train left a station at 12 noon going north at a rate of 50 miles per hour. At 1 p.m., a passenger train left the same station going south at the rate of 60 mph. At what
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Question 255161: A freight train left a station at 12 noon going north at a rate of 50 miles per hour. At 1 p.m., a passenger train left the same station going south at the rate of 60 mph. At what time were the trains 270 miles apart? Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! D=RT
D1=50T FOR THE FREIGHT TRAIN.
D2=60(T-1) FOR THE PASSENGER TRAIN
D1+D2=270
50T+60(T-1)=270
50T+60T-60=270
110T=270+60
110T=330
T=330/110
T=3 HOURS OR @ 3:00 PM. THEY WILL BE 270 MILES APART.
PROOF:
50*3+60(3-1)=270
150+60*2=270
150+120=270
270=270
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