SOLUTION: okay i need help on this problem. I've tried different ways to solve it but i can't seem to the find the answer. I NEED help., PLEASE. Find the standard form of the equation of the

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Question 254976: okay i need help on this problem. I've tried different ways to solve it but i can't seem to the find the answer. I NEED help., PLEASE. Find the standard form of the equation of the line that passes through the point (-3, -5) and is parallel to the line 2x-3y=-6.
Found 2 solutions by drk, richwmiller:
Answer by drk(1908) (Show Source):
You can put this solution on YOUR website!
Here is the question:
(-3, -5) and is parallel to the line 2x-3y=-6.
step 1 - solve the equation for y.

step 2 - find the slope.
Since we have Y = mx + b, the slope is m = 2/3
step 3 - we want parallel. Parallel lines have the same slope so our parallel slope = 2/3
step 4 - using y = mx + b plug in known information to find the b

Step 5 - write the equation.

Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website!
There is the standard form and the slope intercept form.
y=mx+b is the slope intercept form
where m is the slope and b is the y intercept when x=0
The standard form is ax+by=c
where the slope is -a/b
The b's mean different things in each equation. Don't get confused. They are not the same b.
Let's look at your equation 2x-3y=-6
It is in standard form
The slope is -a/b=-(2/-3)=2/3
We want a line parallel which means with the same slope.
(y-y1)=2/3(x-x1)
y-(-3)=2/3(x-(-5))
y+3=2/3(x+5)
y+3=2/3x+2/3(5)
y+3=2x/3+10/3
Subtract 3 from both sides
10/3=3 1/3
y=2x/3+1/3 in slope intercept form
Multiply by 3
3y=2x+1
Subtract 2x
-2x+3y=1 in standard form