Question 254895: Use a coordinate grid to plot ΔABC with vertices having coordinates A(2,6), B(18,2), C(12,12). Is this isosceles, right or equilateral? Where is the midpoint of AB?
Answer by CharlesG2(834) (Show Source):
You can put this solution on YOUR website! Use a coordinate grid to plot ΔABC with vertices having coordinates A(2,6), B(18,2), C(12,12). Is this isosceles, right or equilateral? Where is the midpoint of AB?
distance = sqrt((x2-x1)^2+(y2-y1)^2)
AB=sqrt((18-2)^2+(2-6)^2)=sqrt(16^2+(-4)^2)=sqrt(256+16)=sqrt(272)=16.49
BC=sqrt((12-18)^2+(12-2)^2)=sqrt((-6)^2+10^2)=sqrt(36+100)=sqrt(136)=11.66
CA=sqrt((2-12)^2+(6-12)^2)=sqrt((-10)^2+(-6)^2)=sqrt(100+36)=sqrt(136)=11.66
not equilateral
is isosceles
right triangle would have AB=sqrt(BC^2+CA^2)
sqrt(BC^2+CA^2)=sqrt(136+136)=sqrt(272)=AB
it is isosceles and a right triangle
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