Question 254760: Bob spins 2 spinners; one of which is labelled 1, 2, 3, and the other is labelled A, B, C and D.
Given that all the outcomes are equally likely, find the probability that:
a) the spinner stops at "2" and "C"
b) the spinner stops at "3" and either "B" or "D"
c) the spinners stop at "A" and any number
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Bob spins 2 spinners; one of which is labelled 1, 2, 3, and the other is labelled A, B, C and D.
---
Note: Spinner results are independent.
---------------------
Given that all the outcomes are equally likely, find the probability that:
a) the spinner stops at "2" and "C"
P(2 and C) = P(2)*P(C) = 1/3 * 1/4 = 1/12
---------------------------------------------
b) the spinner stops at "3" and either "B" or "D"
P(3 and (B or D)) = P(3) * P(B or D) = 1/3 * 2/4 = 1/6
-----------------------------------------------
c) the spinners stop at "A" and any number
P(A and any number) = P(A)*P(any number) = (1/4)*1 = 1/4
-----------------------------------------------
Cheers,
stan H.
|
|
|
