SOLUTION: What does x= ? 2log base5(4x+1)=7
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Question 254759
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What does x= ?
2log base5(4x+1)=7
Answer by
edjones(8007)
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2log[5](4x+1)=7
log[5](4x+1)=7/2
5^(log[5](4x+1))=5^(7/2)
4x+1=125sqrt(5)
4x=125sqrt(5)-1
x=(125sqrt(5)-1)/4
.
Ed