SOLUTION: factor completely: a^2-b^2+ac-bc=?

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: factor completely: a^2-b^2+ac-bc=?      Log On


   

Question 254756: factor completely:
a^2-b^2+ac-bc=?
Answer by palanisamy(496) About Me  (Show Source):
You can put this solution on YOUR website!
a^2-b^2+ac-bc=(a+b)(a-b)+c(a-b)
=(a-b)(a+b+c)