Question 254677: you have an equally likely chance of choosing any integer from the set {1,2,3,4,5,6,7,8,9,10,11,12}. find the probability of the given event: A) an even number is chosen, B) a multiple of three is chosen, C) a prime number is chosen, D) a two digit number is chosen.
Found 2 solutions by drk, palanisamy:
Answer by drk(1908)   (Show Source):
You can put this solution on YOUR website! A) an even number is chosen
P(even) = 6/12 = 1/2
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B) a multiple of three is chosen
P(x3) = 4/12 = 1/3
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C) a prime number is chosen
P(prime) = 5/12
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D) a two digit number is chosen
P(2 digit number) = 3/12 = 1/4
Answer by palanisamy(496) (Show Source):
You can put this solution on YOUR website! The given set is {1,2,3,4,5,6,7,8,9,10,11,12}.
We have to choose an integer from this set.
Total number of ways = 12
A) The even numbers are 2,4,6,8,10,12
There are 6 even numbers.
So we can select one in 6 ways.
Probability of choosing an even integer = 6/12 = 1/2
B)a multiple of three is chosen.
The multiples of 3 are 3,6,9,12
There are 4 numbers.
So we can select one in 4 ways.
Probability of choosing a multiple of three = 4/12 = 1/3
C) a prime number is chosen,
The prime numbers are 2,3,5,7,11
There are 5 numbers.
So we can select one in 5 ways.
Probability of choosing a prime = 5/12
D) a two digit number is chosen.
The two digit numbers are 10,11,12
There are 3 numbers.
So we can select one in 3 ways.
Probability of choosing a two digit number = 3/12 = 1/4
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