SOLUTION: Fine two numbers which add to 48 such that twice the smaller number is 6 more than the larger number.

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Question 254605: Fine two numbers which add to 48 such that twice the smaller number is 6 more than the larger number.
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
Let x be smaller number and y = larger number
We have
(i) x+%2B+y+=+48
(ii) 2y+=+x+%2B+6
Solve (i) for x to get
(iii) x+=+48+-+y
By substitution, we get
(iv) 2y = 48-y + 6}}}
and then
3y+=+54
y+=+18
Now, we find x as
x+=+30