SOLUTION: the perimeter of a rectangle is 70 inches the length exceeds the width by 19 inches. Find the length and the width.
Algebra ->
Rectangles
-> SOLUTION: the perimeter of a rectangle is 70 inches the length exceeds the width by 19 inches. Find the length and the width.
Log On
Question 254481: the perimeter of a rectangle is 70 inches the length exceeds the width by 19 inches. Find the length and the width. Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! L=W+19
2L+2W=70
2(W+19)+2W=70
2W+38+2W=70
4W=70-38
4W=32
W=32/4
W=8 ANS. FOR THE WIDTH.
L=8+19=27 ANS. FOR THE LENGTH.
PROOF:
2*27+2*8=70
54+16=70
70=70
(