Question 254302: The greater of two consecutive even integers is ten less than twice the smaller. Find the integers. Found 2 solutions by drk, dabanfield:Answer by drk(1908) (Show Source):
You can put this solution on YOUR website! Let X = first even integer and X+2 = second even integer
(X+2) = 2X - 10
subtract X from both sides to get
2 = X - 10
add 10 to get
12 = X.
Your two numbers are 12 and 14.
You can put this solution on YOUR website! The greater of two consecutive even integers is ten less than twice the smaller. Find the integers.
Let x be the smaller of the two integers. Then the next even integer is x+2.
We are told that:
x+2 = 2*x - 10
Solve for x. The larger integer will then be x+2.
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