SOLUTION: Here is the problem that was given: Ryan Arts manufactures two types of picture frames--let's call them typeX and typeY. Each typeX frame requires 2 hours of labor and 1 unit of m
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-> SOLUTION: Here is the problem that was given: Ryan Arts manufactures two types of picture frames--let's call them typeX and typeY. Each typeX frame requires 2 hours of labor and 1 unit of m
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Question 253993: Here is the problem that was given: Ryan Arts manufactures two types of picture frames--let's call them typeX and typeY. Each typeX frame requires 2 hours of labor and 1 unit of material to make, and each typeY frame requires 1 hour of labor and 2 units of material to make. During the upcoming week the company has 4000 hours of labor and 5000 units of material available. Naturally, during the upcoming week Ryan cannot use more labor or more material than he has available--but he could use less. Write two expressions--one for labor and one for materials--that can be used to model the labor and materials constraints for the upcoming week.
Here is my solution:
x = hours
y = materials
(2,1)
Then the problem was: How many frame of x and how many frame of y can they use?
I have written two expressions:
Labor/hours would be: 2x + y is less than or equal to 4000
Material would be: x + 2y is less than or equal to 5000
His next problem he gave us is the below-mentioned, but I'm confused? Can you please help me.
On a piece of graph paper, graph the two constraints associated with the amount of labor and material that Ryan has available next week. Using your graph, find the set of points that satisfy both constraints: 2X + 1Y <= 4000 and 1X + 2Y <= 5000. How many points are there that satisfy these constraints?
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