You can put this solution on YOUR website! 1)x+y-2z=0
2)3x+y=1
3)5x+3y+7z=2
From equation 1 we have y=2z-x
So if (from equation 2) 3x+y = 1 then
3x+(2z-x)= 1
3x+2z-x = 1
and
From equation 3:
5x+3*(2z-x) + 7z = 2
Solve these two equations for x an z then substitute in the first equation to find y.
You can put this solution on YOUR website! We have three equations:
(i)
(ii)
(iii)
solve (ii) for y. We get
(iv)
substitute (iv) into (i) and (iii) to get 2 equations with two variables.
(v)
(vi)
simplify (v) and (vi) to get
(vii)
multiply (vii) by -2 to get
(ix)
(viii)
add down to eliminate x and solve for z. We get
(x) 11z = 1 - -> z = 1/11.
Find x.
x = 9/11
Find y.
y = -16/22
So, we have
{9/22 , -5/22 , 1/11}