SOLUTION: If a=log(base7)(11-6√2) and b=log(base7)(45+29√2), find 3a+2b in the simplest form.
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-> SOLUTION: If a=log(base7)(11-6√2) and b=log(base7)(45+29√2), find 3a+2b in the simplest form.
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Question 253720
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If a=log(base7)(11-6√2) and b=log(base7)(45+29√2), find 3a+2b in the simplest form.
Answer by
Theo(13342)
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You can
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If
and
, find 3a+2b in the simplest form.
if and only if
if and only if
take log of both sides of first equation to get:
becomes:
this becomes:
divide both sides by log((7)) to get:
*************
take log of both sides of second equation to get:
becomes:
this becomes:
divide both sides by log((7)) to get:
since the denominator is the same, we get:
I don't think you can simplify it any further, but you can solve it using the LOG function of your calculator.
equation becomes:
this becomes:
I confirmed the answer is correct by using the logarithm base conversion formula to convert base 7 logarithm to a base 10 logarithm.
that conversion formula is:
you could also have solved this problem directly by using the base conversion formula.