SOLUTION: Determine whether the given coordinates are the vertices of a triangle. 1. A(3,5), B(4,7), C(7,6) 2. S(6,5), T(8,3), U(12,-1) 3. H(-8,4), I(-4,2), J(4,-2) 4. D(1,-5), E

Algebra ->  Triangles -> SOLUTION: Determine whether the given coordinates are the vertices of a triangle. 1. A(3,5), B(4,7), C(7,6) 2. S(6,5), T(8,3), U(12,-1) 3. H(-8,4), I(-4,2), J(4,-2) 4. D(1,-5), E      Log On


   



Question 253715: Determine whether the given coordinates are the vertices of a triangle.
1. A(3,5), B(4,7), C(7,6)
2. S(6,5), T(8,3), U(12,-1)
3. H(-8,4), I(-4,2), J(4,-2)
4. D(1,-5), E(-3,0), F(-1,0)
5. R(1,3), S(4,0), T(10,-6)
6. W(2,6), X(1,6), Y(4,2)
7. P(-3,2), L(1,1), M(9,-1)
8. B(1,1), C(6,5), D(4,-1)

Found 2 solutions by richwmiller, Edwin McCravy:
Answer by richwmiller(17219) About Me  (Show Source):
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Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
 
I'll just do 1 of each type, number 1 and 3.  The others
are done exactly like one of those. 1 forms a triangle and 3 doesn't.

1. A(3,5), B(4,7), C(7,6)



Yes they do.  How to tell using algebra and without looking at a graph:

Three points either form a triangle or they form a line (said
to be "co-linear")

You find the slopes of the segments joining any two pairs of the
three points.  If they are different, they don't form a straight 
line, and thus they form a triangle. If they have the same slope 
they form a straight line, and do not form a triangle.

So we find the slopes of AB and AC. (We could also have found the
slope of BC, but it is only necessary to find the slopes of two
of the segments:

m%5BAB%5D=%287-5%29%2F%284-3%29=2%2F1=2, m%5BAC%5D=%286-5%29%2F%287-3%29=1%2F4

They are not the same so the points do not lie in a straight line, and
therefore they form a triangle.

3. H(-8,4), I(-4,2), J(4,-2)



No they don't. They form a straight line. How to tell using algebra 
and without looking at a graph:

Three points either form a triangle or they form a line (said
to be "co-linear").  These are co-linear.

You find the slopes of the segments joining any two pairs of the
three points.  If they are different, they don't form a straight 
line, and thus they form a triangle. If they have the same slope 
they form a straight line, and do not form a triangle.

So we find the slopes of HI and IJ. (We could also have found the
slope of HJ, but it is only necessary to find the slopes of two
of the segments:

m%5BHI%5D=%282-4%29%2F%28-4-%28-8%29%29=%28-2%29%2F%28-4%2B8%29=%28-2%29%2F4=-1%2F2, m%5BIJ%5D=%28-2-2%29%2F%284-%28-4%29%29=%28-4%29%2F%284%2B4%29=%28-4%29%2F8=-1%2F2

They are the same so the points lie in a straight line, and
therefore they do not form a triangle.

All the others are like one of these.  You do the rest of them by
yourself.

Edwin