SOLUTION: from his house,matthew walked 4/5 mile to the park.then,he walked 1/10 mile from the park to the library.how much farther was his walk to the park than his walk to the library?
Algebra ->
Percentage-and-ratio-word-problems
-> SOLUTION: from his house,matthew walked 4/5 mile to the park.then,he walked 1/10 mile from the park to the library.how much farther was his walk to the park than his walk to the library?
Log On
Question 253701: from his house,matthew walked 4/5 mile to the park.then,he walked 1/10 mile from the park to the library.how much farther was his walk to the park than his walk to the library? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! from his house,matthew walked 4/5 mile to the park.
then,he walked 1/10 mile from the park to the library.
how much farther was his walk to the park than his walk to the library?
======
difference = park walk - library walk
difference = (4/5)-(1/10) = (8/10)-(1/10) = 7/10 mile
===================================================
Cheers,
Stan H.