SOLUTION: How do you factor the following system of equations? 3x-y=-2 x^3-y=0

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Question 253592: How do you factor the following system of equations?
3x-y=-2
x^3-y=0
Answer by richwmiller(17219) About Me  (Show Source):
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No factoring here, yet!
Solve each for y and then set them equal to each other
3x-y=-2
3x+2=y
x^3-y=0
x^3=y
x^3=3x+2
x^3-3x-2=0
Now we factor
(x-2)(x+1)^2 = 0