SOLUTION: Find a polynomial P(x) of degree 4 with zeros 2,2, 1-√3i, and with constant coefficient of 32. Note: The third zero is one minus radical 3 times i. Which is an imaginary n

Algebra ->  Trigonometry-basics -> SOLUTION: Find a polynomial P(x) of degree 4 with zeros 2,2, 1-√3i, and with constant coefficient of 32. Note: The third zero is one minus radical 3 times i. Which is an imaginary n      Log On


   



Question 253571: Find a polynomial P(x) of degree 4 with zeros 2,2, 1-√3i, and with constant coefficient of 32.
Note: The third zero is one minus radical 3 times i. Which is an imaginary number known as radical negative one.
I am only given 3 zeros but I don't know the fourth zero! Can I assume the fourth zero is just x?
I tried doing the problem:
P(x)= 32 (x-2) (x-2) [x- (1-√3i)]
I got stuck from here. Please help me! Thank you for your time!

Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
We have 2 zeros at 2 and 2.
The third zero is
1+-+isqrt%283%29
The fourth zero is the conjugat of this which is
1+%2B+isqrt%283%29
Remember: imaginaries always occur in pairs.
So, we have

The product of these factors is
P%28x%29+=+%28x%5E2+-4x+%2B+4%29%28x%5E2+-2x+%2B+2%29and then
P%28x%29+=+X%5E4+-10x%5E3+%2B+14x%5E2+-16x+%2B+8
But we wanted 32 as the constant, so multiply by 4 to get
P%28x%29+=+4X%5E4+-40x%5E3+%2B+56x%5E2+-64x+%2B+32