SOLUTION: equations involving radicals check for extraneous solutions square of a-1-5=a

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Question 253569: equations involving radicals check for extraneous solutions
square of a-1-5=a
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
I think this is the question:
%28a-1%29%5E2-5=a
expand the left side to get
a%5E2+-2a+%2B+1-5+=+a
Set this = 0 to get
a%5E2+-+3a+-+4+=+0
factor to get
%28a-4%29%28a%2B1%29+=0
Solve each to get
a-4=0
a = 4
a%2B1=0
a+=+-1
There are no extraneous in this question.